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An incandescent lightbulb emits 96 W of radiation. If the filanent is at a temperature of 3242 K, what is the area of the filament

User Artych
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1 Answer

4 votes

Answer:

1.53 x 10^-5 m^2

Step-by-step explanation:

use the Stefan's law

Energy per unit time = σ x A x T^4

σ = 5.67 x 10 -8 W/m^2 K^4

96 = 5.67 x 10^-8 x A x (3242)^4

A = 1.53 x 10^-5 m^2

User Mikayel Margaryan
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