Question

A concrete piling of 50 kg is suspended from a steel wire of diameter 1.0 mm and length 11.2 m. How much will the wire stretch? modulus for steel is 20 x 10^10 N/m^2.

Answer 1

Step-by-step explanation:

It is given that,

Mass of concrete pilling, m = 50 kg

Diameter of wire, d = 1 mm

Radius of wire, r = 0.0005 m

Length of wire, L = 11.2

Young modulus of steel,
`Y=20* 10^(10)\ N/m^2`

The young modulus of a wire is given by :

`Y=((F)/(A))/((\Delta L)/(L))`

`Y=(F.L)/(A\Delta L)`

`\Delta L=(F.L)/(A.Y)`

`\Delta L=(50\ kg* 9.8\ m/s^2* 11.2\ m)/(\pi (0.0005\ m)^2* 20* 10^(10)\ N/m^2)`

`\Delta L=0.034\ m`

So, the wire will stretch 0.034 meters. Hence, this is the required solution.