Question

on a day when the speed of sound in air is 340 m/s a bat emits a shriek whose echo returns to it 0.0250 seconds later. How far away is the mosquito that reflects back the shriek?

Answer 1

The distance of the mosquito from the bat is 4.25 m.

Step-by-step explanation:

Given that,

Speed of sound in air v= 340 m/s

Time t = 0.0250 second

Let d be the distance of the mosquito from the bat.

The distance traveled by the sound when the echo heard is 2d.

We need to calculate the distance

Using formula of distance

`v = (2d)/(t)`

Put the value into the formula

`v = (2d)/(25*10^(-3))`

`d =(25*10^(-3)*340)/(2)`

`d=4.25\ m`

Hence, The distance of the mosquito from the bat is 4.25 m.