Question

Your swimming pool is square and 5.8 m on a side. It is 4.2 m deep in the morning If the temperature changes by 24 degrees C during the afternoon, how much the depth of the water increase?

Answer 1

The increases depth of the water is 0.021 m.

Step-by-step explanation:

Given that,

One side of square = 5.8 m

Depth = 4.2 m

Temperature = 24°C

Coefficient of volume expansion for water
`\beta = 210*10^(-6)\ /^(\circ)C`

We need to calculate the volume of the pool

`V= 5.8*5.8*4.2`

`V=141.288\ m^3`

Using formula of coefficient of volume expansion

`\Delta V=\Beta V_(0)*\Delta T`

If the temperature changes by 24 degrees C during the afternoon,

`5.8*5.8* h=210*10^(-6)*141.288*24`

`h=(210*10^(-6)*141.288*24)/(5.8*5.8)`

`h=0.021\ m`

Hence. The increases depth of the water is 0.021 m.