Question

Ignoring the mass of the spring, a 5 kg mass hanging from a coiled spring having a constant k= 50 N/m will have a period of oscillation of about: (A) 10 sec., (B) 5 sec., (C) 2 sec., (D) 0.1 secC., (E) 1 min.

Answer 1

Period of oscillation, T = 2 sec

Step-by-step explanation:

It is given that,

Mass of the object, m = 5 kg

Spring constant of the spring, k = 50 N/m

This object is hanging from a coiled spring. We need to find the period of oscillation of the spring. The time period of oscillation of the spring is given by :

`T=2\pi\sqrt{(m)/(k)}`

`T=2\pi\sqrt{(5\ kg)/(50\ N/m)}`

T = 1.98 sec

or

T = 2 sec

So, the period of oscillation is about 2 seconds. Hence, this is the required solution.