Answer:
Net force, F = 7 N
Step-by-step explanation:
It is given that,
Initial kinetic energy of the car,

Final kinetic energy of the car,

Distance, d = 1 m
We need to find the average net force on the car during this interval. It is given by using the work energy theorem as :


Also, W = F.d d = distance and F = net force



F = 7 Newton
So, the average net force on the car during this interval is 7 newton. Hence, this is the required solution.