Question

An unknown material, with a mass of 54 gm, was submerged in water. The object occupied 14 gm of water. What is the density of the material?

Answer 1

Density of unknown material = 3.86 g/cm³

Step-by-step explanation:

Mass of unknown material, M = 54 gm

The object occupied 14 gm of water.

Volume of unknown material = Volume of 14 gm of water.

Density of water = 1 gm/cm³

Volume of 14 gm of water

`V=(14)/(1)=14cm^3`

Volume of unknown material, V = Volume of 14 gm of water = 14 cm³

Density of unknown material

`\rho =(M)/(V)=(54)/(14)=3.86g/cm^3`