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A triangular course for a canoe race is marked with buoys. the first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi. how long is the race?

(the numbers are fractions)

User Fivell
by
5.7k points

2 Answers

4 votes

Answer:

Length of race = 1.2 miles

Explanation:

Length of race is given by the perimeter of triangle.

Refer the given figure.

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.


\texttt{Perimeter =}(3)/(10)+(1)/(2)+(2)/(5)=(3)/(10)+(5)/(10)+(4)/(10)=(3+5+4)/(10)\\\\\texttt{Perimeter =}(12)/(10)=1.2 miles

Length of race = 1.2 miles

A triangular course for a canoe race is marked with buoys. the first leg is 3/10 mi-example-1
User Gal Fridman
by
5.0k points
4 votes

Answer:

1 1/5 mi

Explanation:

We need to add the three legs together

3/10 + 1/2 + 2/5

The common denominator is 10

3/10 =3/10

1/2 *5/5 = 5/10

2/5 *2/2 =4/10

3/10 + 5/10+4/10 = 12/10

10/10 = 10/10+2/10 = 1+2/10 = 1 1/5 mi

User EscalinNancy
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6.0k points