Question

An object of mass 300 g, moving with an initial velocity of 5.00i-3.20j m/s, collides with an sticks to an object of mass 400 g, with an initial velocity of 3.00j. Find magnitude and direction of the final velocity of the composite.

Answer 1

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

Step-by-step explanation:

Mass of object 1 , m₁ = 300 g = 0.3 kg

Mass of object 2 , m₂ = 400 g = 0.4 kg

Initial velocity of object 1 , v₁ = 5.00i-3.20j m/s

Initial velocity of object 2 , v₂ = 3.00j m/s

Mass of composite = 0.7 kg

We need to find final velocity of composite.

Here momentum is conserved.

Initial momentum = Final momentum

Initial momentum = 0.3 x (5.00i-3.20j) + 0.4 x 3.00j = 1.5 i + 0.24 j kgm/s

Final momentum = 0.7 x v = 0.7v kgm/s

Comparing

1.5 i + 0.24 j = 0.7v

v = 2.14 i + 0.34 j

Magnitude of velocity

`v=√(2.14^2+0.34^2)=2.17m/s`

Direction,

`\theta =tan^(-1)\left ( (0.34)/(2.14)\right )=9.03^0`

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.