Question

A 13.1 μF capacitor is connected through a 853 kΩ resistor to a constant potential difference of 64 V. Compute the charge on the capacitor at 14 s after the connections are made. (Give your answer in decimal using micro C (μC) as unit)

Answer 1

`q = 598.9 \mu C`

Step-by-step explanation:

As we know that when an uncharged capacitor is connected through a voltage source then the charge on the plates of capacitor will increase with time.

It is given by the equation

`q = CV(1 - e^{-(t)/(RC)})`

here we know that

`C = 13.1 \mu F`

`R = 853 k ohm`

V = 64 volts

now we have

`q = (13.1 \mu F)(64) ( 1 - e^{-(14)/((853* 10^3)(13.1 * 10^(-6)))})`

`q = 598.9 \mu C`