Question

A 4m^3 container is being filled at a rate of 0.051m^3/s. What is the time required to completely fill this container?

Answer 1

Time required to completely fill this container = 78.43 seconds

Step-by-step explanation:

Volume of container = 4 m³

Rate of filling of container = 0.051 m³/s

We have the equation

`\texttt{Time required}=\frac{\texttt{Volume of container}}{\texttt{Rate of filling of container}}`

Substituting

`\texttt{Time required}=(4)/(0.051)=(4000)/(51)=78.43 s`

Time required to completely fill this container = 78.43 seconds