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HEngi · Answer 1 · 2020-11-03T13:22:30+0000

Answer:

Inductive reactance is 125.7 Ω

Step-by-step explanation:

It is given that,

Inductance,
$L=50\ mH=0.05\ H$

Voltage source, V = 15 volt

Frequency, f = 400 Hz

The inductive reactance of the circuit is equivalent to the impedance. It opposes the flow of electric current throughout the circuit. It is given by :

$X_L=2\pi fL$

$X_L=2\pi * 400\ Hz* 0.05\ H$

$X_L=125.66\ \Omega$

$X_L=125.7\ \Omega$

So, the inductive reactance is 125.7 Ω. Hence, this is the required solution.

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