Answer:
Capacitive reactance is 132.6 Ω.
Step-by-step explanation:
It is given that,
Capacitance,

Voltage source, V = 20 volt
Frequency of source, f = 60 Hz
We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :



So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.