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Inâ 2001, the population in a town was 11% more than it was in 2000. If the population was 25,570 in 2002 which was 10% more than 2001 find the population in 2000

write the number (Round to the nearest wholeâ number.)

User Hetzbh
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1 Answer

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Answer: There was population of 22808 in 2000.

Explanation:

Since we have given that

Population was in 2002 = 25,570

According to question, the population in 2002 was 10% more than 2001.

So, the population in 2001 was


25570=P_1(1+(r)/(100))\\\\25570=P_1(1+(10)/(100))\\\\25570=P_1(1+0.1)\\\\25570=P_1(1.01)\\\\(25570)/(1.01)=P_1\\\\25316.8\approx 25317=P_1

Now, we have given that

In 2001, the population in a town was 11% more than it was in 2000.

So, population in 2000 was


25317=P_0(1+(r)/(100))\\\\25317=P_0(1+(11)/(100))\\\\\25317=P_0(1+0.11)\\\\25317=P_0(1.11)\\\\P_0=(25317)/(1.11)\\\\P_0=22808

Hence, there was population of 22808 in 2000.

User Hvtilborg
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