Answer:
BC and DE
Step-by-step explanation:
In the given figure, the velocity time graph is shown. We know that the area under v-t curve gives the displacement of the particle.
Area under AB,
![d_1=(1)/(2)* 2* 10=10\ m](https://img.qammunity.org/2020/formulas/physics/middle-school/v71wdambfe0i4osvdbkb40z82lrykqd5sb.png)
Area under BC,
![d_2=(1)/(2)* 2* 4=4\ m](https://img.qammunity.org/2020/formulas/physics/middle-school/zqe4qijqwjtd58ii4xjk3hx1ame21cl545.png)
Area under CD,
![d_3=(1)/(2)* 2* 7=7\ m](https://img.qammunity.org/2020/formulas/physics/middle-school/p5qswc81553njz831laik228at20b5x90v.png)
Area under DE,
![d_4=(1)/(2)* 2* 4=4\ m](https://img.qammunity.org/2020/formulas/physics/middle-school/pghmuidoon0km66npbiclc5e0s31tdyz7t.png)
Area under EF,
![d_5=(1)/(2)* 2* 3=3\ m](https://img.qammunity.org/2020/formulas/physics/middle-school/wxrbfez8phpuo6qx4cnhalecbzn1s7z3od.png)
So, form above calculations it is clear that, during BC and DE undergo equal displacement. Hence, the correct option is (c) "BC and DE = 4 meters".