Answer:
The radius is:
![2√(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5y9ofnkra933zp296v31o3wubmdn2pbcli.png)
Explanation:
The equation of a circle in center-radius form is:
![(x - h)^2 + (y - k)^2 = r^2](https://img.qammunity.org/2020/formulas/mathematics/college/2uq784ivfxh92ecn12a9nlwh9u21tin6th.png)
Where the center is at the point (h, k) and the radius is "r".
So, given the equation of the circle:
![x^2+y^2=12](https://img.qammunity.org/2020/formulas/mathematics/high-school/uo72cqye1bl0opce8bqioo8hs4nz1hmf76.png)
You can identify that:
![r^2=12](https://img.qammunity.org/2020/formulas/mathematics/high-school/nl8udns2km8rg6wjx11qzlcn3arfafwzyu.png)
Then, solving for "r", you get that the radius of this circle is:
![r=√(12)\\\\r=2√(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zzi6hxp4jndgc1bx6e9otdkr4ml455hdlv.png)