Question

This is what I am supposed to do, I’m confused on what to do on 3,4, and 5. PLEASE HELP ASAP!!!!!! 30 POINTS!!!!!

Answer 1

see explanation

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

3

Using (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 3, 6)

m =
`(6-0)/(-3-0)` =
`(6)/(-3)` = - 2

Since the line passes through the origin (0, 0) then y- intercept is 0

y = - 2x ← equation of line

4

let (x₁, y₁ ) = (6, 0) and (x₂, y₂ ) = (0, 3)

m =
`(3-0)/(0-6)` =
`(3)/(-6)` = -
`(1)/(2)`

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = -
`(1)/(2)` x + 3 ← equation of line

5

let (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (-2, - 3)

m =
`(-3-3)/(-2-0)` =
`(-6)/(-2)` = 3

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = 3x + 3 ← equation of line