Question

a man bought two calculators at rupees 1250.he sold one at a profit of 2%and next at loss of 3% find cp

Answer 1

the required answer is 125/24.

Answer 2

The cost price of one calculator is Rs.750.

The cost price of other calculator is Rs.500.

Explanation:

Cost price of 1'st calculator = x

Cost price of 2'nd calculator = 1250-x

He sold one at a profit of 2%.

The selling price of one calculator is

`SP_1=CP(1+(P\%)/(100))`

`SP_1=x(1+(2)/(100))`

`SP_1=x(1+0.02)`

`SP_1=1.02x`

He sold other at a loss of 3%.

The selling price of other calculator is

`SP_2=CP(1-(L\%)/(100))`

`SP_2=(1250-x)(1-(3)/(100))`

`SP_2=(1250-x)(1-0.03)`

`SP_2=(1250-x)(0.97)`

`SP_2=1212.5-0.97x`

According to given condition,

`SP_1+SP_2=1250`

`1.02x+1212.5-0.97x=1250`

`0.05x=1250-1212.5`

`0.05x=37.5`

`x=(37.5)/(0.05)`

`x=750`

The cost price of one calculator is Rs.750.

The cost price of other calculator is 1250-750=Rs.500.