Question

Find the limit of the function by using direct substitution. (6 points) limit as x approaches zero of quantity x squared minus three.

Answer 1

`\displaystyle\\\lim_(x\to 0)(x^2-3)=0^2-3=-3`

Answer 2

`\lim_(x \to 0) x^2-3=-3`

Explanation:

This limit can be written as follows

`\lim_(x \to 0) x^2-3`

Direct substitution means that we substitute in the value for x to get our limit

`\lim_(x \to 0) x^2-3\\\\0^2-3\\\\-3`