Question

Write an equation in standard form for each parabola.​

Answer 1

`x=1/4(y-2)^(2)-1`

Explanation:

Use Vertex form:
`x=a(y-k)^(2)+h`

Given: vertek (h, k)=(-1, 2)

`x=a(y-2)^2 -1`

A point:(x , y) = (3, 6)

`3 = a (6-2)^(2) -1`

16a=4, a=1/4

The equation is :
`x=1/4(y-2)^(2)-1`