Question

The point-slope form of the equation of the line that passes through (-4, -3) and (12,1) is y-1=1/4(×-12). What is the standard form of the equation for this line?

Answer 1

x - 4y = 8.

Explanation:

y - 1 = 1/4(x - 12)

y = 1/4x - 3 + 1

y = 1/4x - 2

1/4x - y - 2 = 0

1/4x - y = 2

Multiply through by 4:

x - 4y = 8 is standard form.

Answer 2

x - 4y = 8

Explanation:

We are given point slope form of the equation of the line that passes through the point
`(-4, -3)` and
`(12,1)` which is
`y-1=(1)/(4) (x-12)`.

We are to write this equation in its standard form.

From the given equation, we know that the slope is
`(1)/(4)` so we will find the y intercept.

`y=mx+c`

`1=(1)/(4)* (12) +c`

`c=-2`

Substituting the given values and the y intercept in the standard form of equation.

`y=mx+c`

`y=(1)/(4) x-2`

Rearranging this to get:

x - 4y = 8