Answer:
approximately 27.5 million
Explanation:
If 1990 is the initial year, we will rename it as 0. This is the x coordinate in a pair we will need to write the equation that models this particular situation. The y coordinate that goes along with it is 21.7 (x is time in years, y is number of people). The next coordinate pair we have is (6, 25). If 1990 is year 0, 1996 is year 6.
The standard form for an exponential equation is
![y=a(b)^x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lekphcsob46ocr7m915ck2301mui89r9xb.png)
where y is the number of people, x is the number of years gone by, a is the initial value, and b is the growth rate. We fill in equation 1 with the x and y coordinates from coordinate pair (0, 21.7):
![21.7=a(b)^0](https://img.qammunity.org/2020/formulas/mathematics/college/3vzepiqjtkogab6z45c4vwnpnuz6ili95u.png)
andything rised to the power of 0 = 1, so b raised to 0 = 1:
21.7 = a(1) so
a = 21.7
Now we use coordinate pair (6, 25) in equation 2, subbing in our value for a also:
![25=21.7(b)^6](https://img.qammunity.org/2020/formulas/mathematics/college/ibcnphow1qtg7ek2pojxabq2bptpf0go92.png)
Divide both sides by 21.7 to get
![1.152073733=b^6](https://img.qammunity.org/2020/formulas/mathematics/college/guezdqx0hr8twycc5mnbipczip3weha91q.png)
We "undo" that power of 6 by taking the 6th root of both sides:
![(1.152073733)^{(1)/(6)} =(b^6)^{(1)/(6)}](https://img.qammunity.org/2020/formulas/mathematics/college/7wq8ihtk1zgf6oh9prp5o2teltuovqat01.png)
That gives you that
b = 1.0238 (rounded).
Now that we have a and b, we can write the model for this situation:
![y=21.7(1.0238)^x](https://img.qammunity.org/2020/formulas/mathematics/college/q8fd6lo37549x4bk59hbsyg4ar7f4nkul9.png)
Now that we have the model, we can find y when x = 10 (2010):
![y=21.7(1.0238)^(10)](https://img.qammunity.org/2020/formulas/mathematics/college/rir1gioy4o5fzfqnc1d3d2xke8hprrhk93.png)
First raise 1.0238 to the 10th power to get
y = 21.7(1.266097) and
y = 27.47