Answer:
The speed of the car and the stopping distance are 50.13 m/s and 279.22 m.
Step-by-step explanation:
Given that,
Initial speed = 10.0 m/s
Acceleration = 3.00 m/s^2
Distance


We need to calculate the speed of the car,
Using equation of motion

Where, u = initial velocity
v = final velocity
a = acceleration
Put the value in the equation



(B). We need to calculate the stopping distance of the car,
Using equation of motion again

Here,initial velocity = 50.13 m/s
Final velocity = 0
Acceleration = -4.50 m/s²
Put the value in the equation



Hence, The speed of the car and the stopping distance are 50.13 m/s and 279.22 m.