Question

If the gravitational force between two masses located a distance 100 m apart is F, what would be the force between these objects if the distance between them increases to 800 m?

Answer 1

`(F)/(64)`

Step-by-step explanation:

m = product of masses of two objects

r = distance between the two objects = 100 m

F = initial force between the two object

r' = new distance between the two objects = 800 m

F' = new force between the two objects = ?

k = constant of proportionality

initial force between the two object is given as

`F=(km)/(r^(2))` eq-1

new force between the two objects is given as

`F'=(km)/(r'^(2))` eq-2

Dividing eq-2 by eq-1

`(F')/(F)=(r^(2))/(r'^(2))`

Inserting the values

`(F')/(F)=(100^(2))/(800^(2))`

`F' = (F)/(64)`