Question

Two forces are applied to a 5.0-kg crate; one is 3.0 N to the north and the other is 4.0 N to the east. The magnitude of the acceleration of the crate is: a. 1.0 m/s^2 b. 2.8 m/s^2 c.7.5 m/s^2 d. 10.0 m/s^2

Answer 1

The acceleration of the crate is 1 m/s²

Step-by-step explanation:

It is given that,

Mass of the crate, m = 5 kg

Two forces applied on the crate i.e. one is 3.0 N to the north and the other is 4.0 N to the east. So, there resultant force is :

`F_(net)=√(3^2+4^2) =5\ N`

We need to find the acceleration of the crate. It is given by using the second law of motion as :

`a=(F_(net))/(m)`

`a=(5\ N)/(5\ kg)`

a = 1 m/s²

So, the acceleration of the crate is 1 m/s². Hence, this is the required solution.