Question

A constant force of 120 N pushes a 55 kg wagon across an 8 m level surface. If the wagon was initially at rest, what is the final kinetic energy of the wagon?

Answer 1

The kinetic energy of the wagon is 967.0 J

Step-by-step explanation:

Given that,

Force = 120 N

Mass = 55 kg

Height = 8 m

We need to calculate the kinetic energy of the wagon

Using newtons law

`F = ma`

`(120)/(55)=a`

`a =2.2\ m/s^2`

Using equation of motion

`v^2 =u^2+2as`

Where,

v = final velocity

u = initial velocity

s = height

Put the value in the equation

`v^2=0+2*2.2*8`

`v=5.93\ m/s`

Now, The kinetic energy is

`K.E=(1)/(2)mv^2`

`K.E=(1)/(2)*55*(5.93)^2`

`K.E=967.0\ J`

Hence, The kinetic energy of the wagon is 967.0 J