Answer:
213.18 volt
Step-by-step explanation:
N = 500, A = 0.02 m^2, B = 0.30 T, f = 960 rpm = 960 / 60 = 16 rps
The maximum value of induced emf is given by
e0 = N x B x A x ω
e0 = N x B x A x 2 x π x f
e0 = 500 x 0.3 x 0.02 x 2 x 3.14 x 16
e0 = 301.44 Volt
The rms value of induced emf is given by
![e_(rms) = (e_(0))/(√(2))](https://img.qammunity.org/2020/formulas/physics/college/qz8xrem3hmwhssnu9hncskcec3cmthfktr.png)
![e_(rms) = (301.44)/(√(2))](https://img.qammunity.org/2020/formulas/physics/college/meb99hk052jypxkg7te8smq1skhozoylxc.png)
e rms = 213.18 volt