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A = 8, b = 4, and c = 16

A = 8, b = 4, and c = 16-example-1
User WEBjuju
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2 Answers

16 votes
16 votes

Answer:


3 (4)/(31)

Explanation:


\frac{2(4) + 3(16) {}^(2) }{4(8) {}^(2) - 2(4) }


(776)/(248)


3 (4)/(31)

User Hemant Chittora
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3.0k points
22 votes
22 votes

Answer:
\sf 3(4)/(31) \quad or \quad (97)/(31)

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The given expression:


\sf (2b + 3c^2)/(4a^2 - 2b)

Here given a = 8, b = 4, and c = 16

Inserting this values


\sf (2(4) + 3(16)^2)/(4(8)^2 - 2(4))

Simplify following


\sf (8 + 3(256))/(4(64) - 8)

Distribute inside parenthesis


\sf (8 + 768)/(256 - 8)

Add/Subtract similar terms


\sf (776)/(248)

Simplify following, in improper fraction


\sf (97)/(31)

In mixed fraction, answer:


\sf 3(4)/(31)

User STaefi
by
3.0k points