Question

An object of weight 8N is moving along a horizontal plane. If the coefficient of kinetic friction is 0.25 find the friction force acting on the object.

Answer 1

2 N

Step-by-step explanation:

Wight of object = mg = 8 N

Coefficient of friction, u = 0.25

The normal reaction acting on the object = N = mg = 8 N

According to the laws of limiting friction,

The friction force, f = uN

f = 0.25 x 8 = 2 N