Question

A vertical spring (ignore its mass), whose spring constant is 594-N/m, is attached to a table and is compressed down by 0.196-m. What upward speed (in m/s) can it give to a 0.477-kg ball when released?

Answer 1

Speed, v = 6.91 m/s

Step-by-step explanation:

Given that,

Spring constant, k = 594 N/m

It is attached to a table and is compressed down by 0.196 m, x = 0.196 m

We need to find the speed of the spring when it is released. Here, the elastic potential energy is balanced by the kinetic energy of the spring such that,

`(1)/(2)kx^2=(1)/(2)mv^2`

`v=\sqrt{(kx^2)/(m)}`

`v=\sqrt{(594\ N/m* (0.196\ m)^2)/(0.477\ kg)}`

v = 6.91 m/s

So, the speed of the ball is 6.91 m/s. Hence, this is the required solution.