Answer:
![T_c=-210.15^(\circ)C](https://img.qammunity.org/2020/formulas/physics/college/w1f3nhkxjycjtkuarw8dnffu5m1975ryqn.png)
Step-by-step explanation:
In this question we need to convert the temperature in kelvin to degree Celsius. The conversion from kelvin scale to Celsius scale is as follows :
![T_k=T_c+273.15](https://img.qammunity.org/2020/formulas/physics/college/o8uvm01o9odg2xa7bm7j4izmnt0ok3qqsz.png)
Here,
![T_k=63\ K](https://img.qammunity.org/2020/formulas/physics/college/anyrynhpq50ufzbm7fql2q3l0bo2o1enuf.png)
![T_k-273.15=T_c](https://img.qammunity.org/2020/formulas/physics/college/gdtyfjkehxg3lzh1bxx1ykrur6ze6ij40a.png)
![63-273.15=T_c](https://img.qammunity.org/2020/formulas/physics/college/ua16px16cnjhtujr1fk81lt9fnyt7c4bj3.png)
![T_c=-210.15^(\circ)C](https://img.qammunity.org/2020/formulas/physics/college/w1f3nhkxjycjtkuarw8dnffu5m1975ryqn.png)
Here, negative sign shows that the heat is released. So, the temperature at 63 K is equivalent to 210.15 °C. Hence, this is the required solution.