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You heat a 541cm^3 sample of a substance from 133°C to 273°C and find that its volume increases by 2.25 cm^3. Calculate the coefficient of volume expansion of this substance.

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Answer:


\gamma = 2.97 * 10^(-5) per ^0 C

Step-by-step explanation:

As we know by the theory of expansion the change in the volume of the object is directly proportional to change in temperature and initial volume.

So here we can say


\Delta V = V_0\gamma \Delta T

here


\gamma = coefficient of volume expansion

so we have


\gamma = (\Delta V)/(V_0 \Delta T)

now plug in all values


\gamma = (2.25 cm^3)/((541 cm^3)(273 - 133))


\gamma = 2.97 * 10^(-5) per ^0 C

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