Answer:
![\gamma = 2.97 * 10^(-5) per ^0 C](https://img.qammunity.org/2020/formulas/physics/college/buqoaau30hi7f0up9ksw869tmjxj70k0hs.png)
Step-by-step explanation:
As we know by the theory of expansion the change in the volume of the object is directly proportional to change in temperature and initial volume.
So here we can say
![\Delta V = V_0\gamma \Delta T](https://img.qammunity.org/2020/formulas/physics/college/twmcqhf2f4l46py90y6h4blovwlpxf0ll2.png)
here
= coefficient of volume expansion
so we have
![\gamma = (\Delta V)/(V_0 \Delta T)](https://img.qammunity.org/2020/formulas/physics/college/6lpgmq7w3efelflcqjeindb5nulhtqax9h.png)
now plug in all values
![\gamma = (2.25 cm^3)/((541 cm^3)(273 - 133))](https://img.qammunity.org/2020/formulas/physics/college/m4bip82q2zpp5xi3ye9ucmdsfnaznvjk8e.png)
![\gamma = 2.97 * 10^(-5) per ^0 C](https://img.qammunity.org/2020/formulas/physics/college/buqoaau30hi7f0up9ksw869tmjxj70k0hs.png)