Question

A string is wrapped around a pulley of radius 3.60 cm , and a weight hangs from the other end. The weight falls with a constant acceleration 3.00 m/s^2 What's the angular acceleration of the pulley?

Answer 1

83.3 rad/s^2

Step-by-step explanation:

r = 3.6 cm = 0.036 m

a = 3 m/s^2

the relation between the linear acceleration and angular acceleration is given by

a = r α

where, α is angular acceleration, a be the linear acceleration.

α = a / r

α = 3 / 0.036 = 83.3 rad/s^2