Answer:
The current is 2.0 A.
(A) is correct option.
Step-by-step explanation:
Given that,
Length = 150 m
Radius = 0.15 mm
Current density
![J=2.8*10^(7)\ A/m^2](https://img.qammunity.org/2020/formulas/physics/college/247otaaj8oyohm20gd4ub4wiq2rzxntqfo.png)
We need to calculate the current
Using formula of current density
![J = (I)/(A)](https://img.qammunity.org/2020/formulas/physics/college/n23h4ghqy0xxxp2s5ahova9vl8an86gd6u.png)
![I=J*A](https://img.qammunity.org/2020/formulas/physics/college/id13rj01i2z4qe3wb1c5kg0eqv8pinwnr9.png)
Where, J = current density
A = area
I = current
Put the value into the formula
![I=2.8*10^(7)*\pi*(0.15*10^(-3))^2](https://img.qammunity.org/2020/formulas/physics/college/yql0ri7uk9n1r8egb0r21wz5tuw5uhx6g1.png)
![I=1.97=2.0\ A](https://img.qammunity.org/2020/formulas/physics/college/uqhdumvqokq0zd774j83rl1uoilyq5cstf.png)
Hence, The current is 2.0 A.