Question

A vector has components Ax = 52.0 m and Ay = 41.0 m. Find: (a) The length of the vector A.

(b) The angle it makes with the x-axis (in degrees).

Answer 1

Part a)

A = 66.2 m

Part b)

Angle = 38.35 degree

Step-by-step explanation:

Part a)

Length of the vector is the magnitude of the vector

here we know that

`A_x = 52.0 m`

`A_y = 41.0 m`

now we have

`A = √(A_x^2 + A_y^2)`

`A = √(52^2 + 41^2)`

`A = 66.2 m`

Part b)

Angle made by the vector is given as

`tan\theta = (A_y)/(A_x)`

`tan\theta = (41)/(52)`

`\theta = 38.25 degree`