Question

A bicycle generator rotates at 154 rads/s, producing an 16.5 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.68 T field. How many turns are in the coil?

Answer 1

N = 525 Turns

Step-by-step explanation:

Peak Voltage of a coil is given by the formula

`V_(peak) = NBA\omega`

here we know that

`V_(peak) = 16.5 Volts`

B = 0.68 T

`\omega = 154 rad/s`

`Area = (0.01 m)* (0.03 m)`

`Area = 3 * 10^(-4) m^2`

now we have

`16.5 = N(0.68)(3 * 10^(-4))(154)`

`N = 525`

Answer 2

525.2

Step-by-step explanation:

w = 154 rad/s, e0 = 16.5 V, A = 1 x 3 = 3 cm^2 = 3 x 10^-4 m^2, B = 0.68 T

Let the number of turns be N.

By use of law of electromagnetic induction

e0 = N B A w

16.5 = N x 0.68 x 3 x 10^-4 x 154

N = 525.2