Question

A 3.00-L flask is filled with gaseous ammonia, NH3. The gas pressure measured at 27.0 ∘C is 2.55 atm . Assuming ideal gas behavior, how many grams of ammonia are in the flask? Express your answer to three significant figures and include the appropriate units.

Answer 1

Answer : The mass of ammonia present in the flask in three significant figures are, 5.28 grams.

Solution :

Using ideal gas equation,

`PV=nRT\\\\PV=(w)/(M)* RT`

where,

n = number of moles of gas

w = mass of ammonia gas = ?

P = pressure of the ammonia gas = 2.55 atm

T = temperature of the ammonia gas =
`27^oC=273+27=300K`

M = molar mass of ammonia gas = 17 g/mole

R = gas constant = 0.0821 L.atm/mole.K

V = volume of ammonia gas = 3.00 L

Now put all the given values in the above equation, we get the mass of ammonia gas.

`(2.55atm)* (3.00L)=(w)/(17g/mole)* (0.0821L.atm/mole.K)* (300K)`

`w=5.28g`

Therefore, the mass of ammonia present in the flask in three significant figures are, 5.28 grams.