Answer:
![T_C=256.2^(\circ)C](https://img.qammunity.org/2020/formulas/physics/college/tsosukpgd3z5mlcirg67aplmlfdx2yvmui.png)
Step-by-step explanation:
Given that,
Efficiency of heat engine,
![\eta=40\%=0.4](https://img.qammunity.org/2020/formulas/physics/college/5a4etir4e4weoa3gasf2wyxeiql3k43v2o.png)
Temperature of hot source,
![T_H=427^(\circ)C](https://img.qammunity.org/2020/formulas/physics/college/m58086mqo4ca26sc93fat9d1vcgpn8jsvv.png)
We need to find the temperature of cold sink i.e.
. The efficiency of heat engine is given by :
![\eta=1-(T_C)/(T_H)](https://img.qammunity.org/2020/formulas/physics/college/kt9fj6jgi7x6qcbk6ts9j060j2b3r909s4.png)
![T_C=(1-\eta)T_H](https://img.qammunity.org/2020/formulas/physics/college/h31htog4ov83gpogax61orhvlyzhrslop7.png)
![T_C=(1-0.4)* 427](https://img.qammunity.org/2020/formulas/physics/college/60klqpt66noy46kpqhxenba8znizr8i6yt.png)
![T_C=256.2^(\circ)C](https://img.qammunity.org/2020/formulas/physics/college/tsosukpgd3z5mlcirg67aplmlfdx2yvmui.png)
So, the temperature of the cold sink is 256.2°C. Hence, this is the required solution.