Question

A 0.8 g object is placed in a 159 N/C uniform electric field. Upon being released from rest, it moves 72 m in 2.9 s. Determine the object's acceleration & charge magnitude. Assume the acceleration is due to the E-field (i.e., ignore all other forces). a =

Answer 1

The acceleration and charge are 17.122 m/s² and
`8.6*10^(-5)\ C`

Step-by-step explanation:

Given that,

Mass of object = 0.8 g

Electric field = 159 N/C

Distance = 72 m

Time = 2.9 s

We know that,

The electric force is

`F = Eq`....(I)

The newton's second law

`F=ma`

Put the value of F in the equation (I)

`ma=Eq`...(II)

We calculate the acceleration

Using equation of motion

`s=ut+(1)/(2)at^2`

`a =(2s)/(t^2)`

`a=(2*72)/((2.9)^2)`

`a=17.122\ m/s^2`

From equation (II)

`q=(ma)/(E)`

`q=(0.8*10^(-3)*17.122)/(159)`

`q=0.000086148427673\ C`

`q=8.6*10^(-5)\ C`

Hence, The acceleration and charge are 17.122 m/s² and
`8.6*10^(-5)\ C`