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5. (9) Letf- ((-2, 3), (-1, 1), (0, 0), (1,-1), (2,-3)) and let g- ((-3, 1), (-1, -2), (0, 2), (2, 2), (3, 1)j. Find: a. (g f (0) c. (f ° g)(2)

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Answer: g(f(0)) = 2 and (f ° g)(2) = -3.

Step-by-step explanation: We are given the following two functions in the form of ordered pairs :

f = {(-2, 3), (-1, 1), (0, 0), (1,-1), (2,-3)}

g = {(-3, 1), (-1, -2), (0, 2), (2, 2), (3, 1)} .

We are to find g(f(0)) and (f ° g)(2).

We know that, for any two functions p(x) and q(x), the composition of functions is defined as


(p\circ q)(x)=p(q(x)).

From the given information, we note that

f(0) = 0, g(0) = 2, g(2) = 2 and f(2) = -3.

So, we get


g(f(0))=g(0)=2,\\\\(f\circ g)(2)=f(g(2))=f(2)=-3.

Thus, g(f(0)) = 2 and (f ° g)(2) = -3.

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