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Question 15 of 20 (1 point) View problem in a pop-up Assume that the mean systolie blood pressure of normal adults is 120 millimeters of mercury (mm Hg) and the standard deviation is 5.6. Assume the variable is normally distributed. Use a graphing calculator and round the answers to four decimal places. Part 1 If an individual is selected, find the probability that the individual's pressure will be between 120.4 and 121.9 mm Hg. P120A

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Answer: 0.1052

Explanation:

Given : Mean :
\mu= 120

Standard deviation :
\sigma= 5.6

We assume the variable is normally distributed.

The formula for z-score is given by :-


z=(x-\mu)/(\sigma)

For x=120.4


z=(120.4-120)/(5.6)=0.0714285714286\approx0.07

For x=121.9


z=(121.9-120)/(5.6)=0.339285714286\approx0.34

The p-value =
P(0.07<z<0.34)=P(0.34)-P(0.07)


=0.6330717-0.5279031=0.1051686\approx0.1052

The probability that the individual's pressure will be between 120.4 and 121.9 mm Hg = 0.1052

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