Question

A very light ideal spring having a spring constant (force constant) of 8.2 N/cm is used to lift a 2.2-kg tool with an upward acceleration of 3.25 m/s2. If the spring has negligible length when it us not stretched, how long is it while it is pulling the tool upward?

Answer 1

x = 3.5 cm

Step-by-step explanation:

When spring is used as a lift tool

so the mass suspended on it will have spring force on it

So as per the force equation of mass we can say

`F_(net) = ma`

now net force on the mass is

`F_(net) = kx - mg`

`F_(net) = kx - mg = ma`

here we have

`kx = mg + ma`

now we have

`x = (mg + ma)/(k)`

`x = (2.2(9.8) + 2.2(3.25))/(8.2)`

`x = 3.5 cm`