Answer:
![\large\boxed{Q5.\ x=45\sqrt2}\\\boxed{Q6.\ x=8\sqrt2,\ y=4\sqrt6}](https://img.qammunity.org/2020/formulas/mathematics/high-school/cd4iopv6w05dui6tqs6e9i4i64g065hp00.png)
Explanation:
Q5.
x it's a diagonal of a square.
The formula of a length of diagonal of a square:
![d=a\sqrt2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/afs7kn0ghl3cq4o4uay9sr5hec7h1hseu6.png)
a - side of a square
We have a = 45.
Substitute:
![x=45\sqrt2](https://img.qammunity.org/2020/formulas/mathematics/high-school/xc1hbrrheyu43aox6x5tcs2j1fn18g71vx.png)
Q6.
Look at the first picture.
In a triangle 45° - 45° - 90°, all sides are in ratio 1 : 1 : √2.
In a triangle 30° - 60° - 90°, all sidea are in ratio 1 : √3 : 2.
Look at the second picture.
from the triangle 45° - 45° - 90°
multiply both sides by √√2 (use √a · √a = a)
divide both sides by 2
![a=4\sqrt2](https://img.qammunity.org/2020/formulas/mathematics/high-school/pcj0ypouaiss0fx9enluygzrpqcgfckkqe.png)
from the triangle 30° - 60° - 90°
![x=2a\to x=2(4\sqrt2)=8\sqrt2](https://img.qammunity.org/2020/formulas/mathematics/high-school/j0u8mqcgv5z0jilpmazadsrhf1t2ikqpaw.png)
![y=a\sqrt3\to y=(4\sqrt2)(\sqrt3)=4\sqrt6](https://img.qammunity.org/2020/formulas/mathematics/high-school/lymkvk3pvtypujyp9dwv8enpe7xmu0kfnf.png)