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Let f(x)=x^7-4e^x

A) f'(-1)
b)f''(-1)

1 Answer

3 votes

Answer:

Explanation:

Let f(x) = x^7 - 4e^x .

Then f '(x) = 7x^6 - 4e^x, and

f "(x) = 42x^5 - 4e^x, and so:

f '(-1) = 7(-1)^6 - 4e^(-1) = 7 + 4/e

and

f "(x) = 42(-1)^5 - 4e^(-1) = -42 + 4/e

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