Question

Let f(x)=x^7-4e^x

A) f'(-1)
b)f''(-1)

Answer 1

Explanation:

Let f(x) = x^7 - 4e^x .

Then f '(x) = 7x^6 - 4e^x, and

f "(x) = 42x^5 - 4e^x, and so:

f '(-1) = 7(-1)^6 - 4e^(-1) = 7 + 4/e

and

f "(x) = 42(-1)^5 - 4e^(-1) = -42 + 4/e