Question

Find the area of triangle ABC.

A = 34.5°, b = 13.2 in., c = 5.3 in.

Answer 1

Answer:19.812

Explanation:

Given

angle A=34.5

b=13.2 in.

c=5.3 in.

Area of triangle when two sides and angle between them is given

`A=(1)/(2)bcsina`

`A=(1)/(2)\left ( 13.2\right )\left ( 5.3\right )sin\left ( 34.5\right )`

`A=19.812 in.^2`

Answer 2

=19.81 in²

Explanation:

We use the sine formula to find the area of the triangle in question.

In this formula we find the product of two adjoined sides with the sine of the angle between them.

The sides b and c are bound by the angle A.

Therefore area=1/2bcSin A

A=1/2×13.2 in×5.3 in× Sin 34.5

=19.81 in²