Question

If a 2 inch diameter rod is subjected to a centric tensile axial load of 15.71 kip, what is the average normal stress (ksi) to three significant figures?

Answer 1

The average normal stress is 5 ksi.

Step-by-step explanation:

Given that,

Diameter = 2 inch

Load = 15.71 kip

We need to calculate the average normal stress

Using formula of stress

Average normal stress
`\sigma =(F)/(A)`

Where, F = load

A = area

Put the value into the formula

`\sigma=(15.71)/(\pi*((2)/(2))^2)`

`\sigma = 5\ kip/inc^2`

`\sigma=5\ ksi`

Hence, The average normal stress is 5 ksi.