Answer:
23.5 J/Kg °C
Step-by-step explanation:
The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree Celcius.
c = Q / m ΔT
Here, Q / m = 282 J/kg, ΔT = 12
So, the specific heat = 282 / 12 = 23.5 J/Kg °C
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