Question

Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. Then the rate of heat transfer to the water is 225.7 kJ/min 45.1 kJ/min 53.5 kJ/min 0.84 kJ/min 41.8 kJ/min

Answer 1

Rate of heat is 45.1 kJ/min

Step-by-step explanation:

Heat required to evaporate the water is given by

Q = mL

here we know that

`L = 2.25 * 10^6 J/kg`

now we have

`Q = (0.200)(2.25 * 10^6 J/kg)`

`Q = 452.1 kJ`

now the power is defined as rate of energy

`P = (Q)/(t)`

`P = (452.1 kJ)/(10)`

`P = 45.1 kJ/min`