Answer:
Percentage increase in the fundamental frequency is
d)-14.02%
Step-by-step explanation:
As we know that fundamental frequency of the wave in string is given as
![f_o = (1)/(2L)\sqrt{(T)/(\mu)}](https://img.qammunity.org/2020/formulas/physics/college/cojaql5an51ju42841355flcyo1it19bnq.png)
now it is given that tension is increased by 30%
so here we will have
![T' = T(1 + 0.30)](https://img.qammunity.org/2020/formulas/physics/college/ngxubzy706x9cxr5mq98adghbyxt5coeud.png)
![T' = 1.30T](https://img.qammunity.org/2020/formulas/physics/college/5086vhwp7qy8bwqhx9d6m0m733t0y07go6.png)
now new value of fundamental frequency is given as
![f_o' = (1)/(2L)\sqrt{(1.30T)/(\mu)}](https://img.qammunity.org/2020/formulas/physics/college/o6n04vh80xkjisotkhsito74c58jbnq0xp.png)
now we have
![f_o' = √(1.3)f_o](https://img.qammunity.org/2020/formulas/physics/college/8t3h90guivkoupygxxv1j7hu78didubv4r.png)
so here percentage change in the fundamental frequency is given as
![change = (f_o' - f_o)/(f_o) * 100](https://img.qammunity.org/2020/formulas/physics/college/ye6chgbf3op3ujmhqvsjt6ww15jjmzgt3j.png)
% change = 14.02%