Question

Water at 0°C loses 1140 calories worth of heat. How much of the water freezes? [Lf= 79.7 cal/g] a) 16.8 g b) 81.5 g c) 0.002 g d) 14.3 g e) 51.0 g

Answer 1

option d)

Step-by-step explanation:

The amount of heat required to convert the 1 g of ice at 0 degree C to 1 g water at 0 degree C is called latent heta of fusion.

H = m Lf

where,, h is the heat required, m is the mass and Lf is the latent heat of fusion

1140 = m x 79.7

m = 14.3 g